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5x^2-12x=-6x+15
We move all terms to the left:
5x^2-12x-(-6x+15)=0
We get rid of parentheses
5x^2-12x+6x-15=0
We add all the numbers together, and all the variables
5x^2-6x-15=0
a = 5; b = -6; c = -15;
Δ = b2-4ac
Δ = -62-4·5·(-15)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{21}}{2*5}=\frac{6-4\sqrt{21}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{21}}{2*5}=\frac{6+4\sqrt{21}}{10} $
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